I have a question abourt some calculus in an article, I found it in the internet but I didn't understood some steps. his is the link of the article;
http://arxiv.org/abs/math/0311352
In the first paragraph of page 19 the author says :
Let
and|Y(p)|= sinh(distance(a,p)),for every p;) of Hn+1.Therefore, along the sphere S we have Y= sinh;);).
I don't understand why (a,p)=cosh(distance(a,p))) and |Y(p)|= sinh(distance(a,p)).
Please help me because I will presnet this work in my class next week and I have no idea about the detail of calculus
