Forum de Mathématiques: Maths-Forum

Merci pour les réponses, c'est plus clair. Et j'ai fait les 10 exercices partagés par Pisigma, merci pour le partage.
[url="https://routerlogin.ltd/"]router login[/url]

[url="https://pikashow.ltd/"]watch IPL[/url]

We want to return angles in a range that correspond to all possible inputs, but only one input that produces each output.

For example, sin between pi/2 and pi is always positive, so inverse sin of -1 wouldn't return anything useful if the range was restricted to those values.