NI = linspace(1,N,N)
E = 1/5.*E
ESP = sum(NI.*E)
printf("Valeur de l''espérance ESP(Y) = %0.3f",ESP)
-->1/5.*E
ans =
column 1 to 11
0. 0. 0. 0. 0.0384 0.0768 0.09984 0.10752 0.1045094 0.0954778 0.0838164
column 12 to 20
0.0716390 0.0601130 0.0497916 0.0408620 0.0333101 0.0270216 0.0218420 0.0176086 0.0141679
column 21 to 29
0.0113830 0.0091357 0.0073261 0.0058714 0.0047034 0.0037665 0.0030155 0.0024138 0.0019318
column 30 to 38
0.0015460 0.0012371 0.0009898 0.0007920 0.0006336 0.0005069 0.0004056 0.0003245 0.0002596
column 39 to 47
0.0002077 0.0001661 0.0001329 0.0001063 0.0000851 0.0000681 0.0000544 0.0000436 0.0000348
column 48 to 56
0.0000279 0.0000223 0.0000178 0.0000143 0.0000114 0.0000091 0.0000073 0.0000058 0.0000047
column 57 to 65
0.0000037 0.0000030 0.0000024 0.0000019 0.0000015 0.0000012 0.0000010 0.0000008 0.0000006
column 66 to 74
0.0000005 0.0000004 0.0000003 0.0000003 0.0000002 0.0000002 0.0000001 0.0000001 8.425D-08
column 75 to 83
6.740D-08 5.392D-08 4.314D-08 3.451D-08 2.761D-08 2.209D-08 1.767D-08 1.413D-08 1.131D-08
column 84 to 92
9.046D-09 7.237D-09 5.790D-09 4.632D-09 3.705D-09 2.964D-09 2.371D-09 1.897D-09 1.518D-09
column 93 to 100
1.214D-09 9.713D-10 7.771D-10 6.217D-10 4.973D-10 3.979D-10 3.183D-10 2.546D-10
MJoe a écrit:@leon1789, tu voulais dire le 28ème jour avec une probabilité de 0,9903347, soit 99,03347 %
Valeur de ma matrice F :
column 1 to 12
0. 0. 0. 0. 0. 0.0384 0.1152 0.21504 0.32256 0.4270694 0.5225472 0.6063636
column 13 to 21
0.6780027 0.7381157 0.7879072 0.8287693 0.8620793 0.8891010 0.9109429 0.9285515 0.9427194
column 22 to 30
0.9541025 0.9632381 0.9705642 0.9764355 0.9811390 0.9849055 0.9879210 0.9903347 0.9922666
column 31 to 39
0.9938125 0.9950496 0.9960394 0.9968314 0.9974650 0.9979719 0.9983775 0.9987020 0.9989616
column 40 to 48
0.9991693 0.9993354 0.9994683 0.9995747 0.9996597 0.9997278 0.9997822 0.9998258 0.9998606
column 49 to 57
0.9998885 0.9999108 0.9999286 0.9999429 0.9999543 0.9999635 0.9999708 0.9999766 0.9999813
column 58 to 66
0.9999850 0.9999880 0.9999904 0.9999923 0.9999939 0.9999951 0.9999961 0.9999969 0.9999975
column 67 to 75
0.9999980 0.9999984 0.9999987 0.9999990 0.9999992 0.9999993 0.9999995 0.9999996 0.9999997
column 76 to 84
0.9999997 0.9999998 0.9999998 0.9999999 0.9999999 0.9999999 0.9999999 0.9999999 1.0000000
column 85 to 93
1.0000000 1.0000000 1.0000000 1.0000000 1.0000000 1.0000000 1.0000000 1.0000000 1.0000000
column 94 to 100
1. 1. 1. 1. 1. 1. 1.
Arbre a écrit:Un petit défi qui sait calculer la proba en 100 jours de manger tout les kiwis, avec au départ 10 kiwi ?
N = 100000
P = zeros(1,N)
for i = 1:N
K = ones(1,100)
p = 0
while p <> 400
p = p + 1
j = int(100*rand() + 1)
if K(1,j) == 1 then
K(1,j) = 0
end
end
if sum(K) == 0 then
P(1,i) = 1
end
end
q = sum(P)/N
printf("Probabilité P(Y = 400)= %0.3f",q)
Utilisateurs parcourant ce forum : Aucun utilisateur enregistré et 8 invités
Tu pars déja ?
Identification
Pas encore inscrit ?
Ou identifiez-vous :