Bonjour
je voulais ajouter le commentaire ci dessous (partie en Anglais), mais pour une raison que j'ignore ,
je ne peux mettre un commentaire.
si j'ajoute un commentaire celui ci apparait mais disparait si je rafraichi la page de la video.
si quelqu'un ici a la patience de lire la Video et de repondre a ma question ci dessous .
Lie groups and Lie algebras: A local logarithm
https://www.youtube.com/watch?v=VhxCaDC ... q9qe7k1nyr
I allow myself to add here a practical example in dimension 2 to illustrate this video,
maybe it can help other people like me who had difficulty understanding this video.
https://sagecell.sagemath.org/?q=fqhjtp
but I don't understand the last part of this video. I understand that d A_ {i, j) / d A_ {i, j) = 1
but I don't understand why d A_ {i, j) / d A_ {i, k) = 0.
imagine that A = matrix ([[e ^ (x0 - x1) -e ^ (x0 - x1)], [e ^ x0 e ^ x1]])
and take d A_ {0,0) / d A_ {1,0) => d {e ^ (x0 - x1)} / d {e ^ x0}, then if e ^ x0 varies then e ^ (x0 - x1) also varies
and therefore d A_ {0,0) / d A_ {1,0)! = 0 ? but maybe this does not apply to any matrices A which are commuting ?
what particular type of matrix A does d A_ {i, j) / d A_ {n, m) = 0 apply to?
but i guess there is something important here that i didn't understand ! Sorry if my question is stupid.
Lie group and Lie Algebra playList
https://www.youtube.com/playlist?list=P ... q9qe7k1nyr