Forum de Mathématiques: Maths-Forum

Bonjour ! Exercice 2 : 1) (1+t/100)² = 1.92 cm1 = 1+ (20/100) = 1.2 cm2 = 1+(60/100) = 1.6 cm = 1.2x1.6 = 1.92 donc t est la solution de l'équation ( 1+ t/100)² = 1.92 2) (1+20/100) x(1+60/100) = (1 +0.2 ) x ( 1+ 0.6) = 1.2 x 1.6 = 1.92 1.92 - 1 = 0.92 x 100 = 92 % 3) Exercice 3 : 1) 2) 2x² - 300x +...