Prove

[Branza]

demnostrate that:

*pls try in english.

[acoustica]

demnostrate that:

*pls try in english.

In french, we say an "universe number", so there is no periodic serie of numbers. In fact, if want to have "54400012646781100078765557", you can, as for every serie of numbers.

For the demonstration, you can have how many "0" one after the other that you want

[Branza]

In french, we say an "universe number", so there is no periodic serie of numbers. In fact, if want to have "54400012646781100078765557", you can, as for every serie of numbers.

For the demonstration, you can have how many "0" as you want. :happy2:

If i understand what you wrote goodly then i say that the problem have not solution.
*i saw the problem into the book and the auther precise that the problem have solution(demonstration).

[acoustica]

If i understand what you wrote goodly then i say that the problem have not solution.
*i saw the problem into the book and the auther precise that the problem have solution(demonstration).

I changed slightly what I've written. Is it better? :happy2:

[Branza]

I changed slightly what I've written. Is it better? :happy2:

from what u wrote i understand that any number that not have any periodic figure then the number in R/Q.

[acoustica]

from what u wrote i understand that any number that not have any periodic figure then the number in R/Q.

Yes. Just a queston: when you write R/Q, it is R but not Q?
If it is so, that is i've said: if n is a number of Q, then, you can find p and q of N, so that and n has a periodic writing:
n=a,bcd...bcd...bcd, or just n=a,bbbb... or a=a,bcbcbc...

[Branza]

Yes. Just a queston: when you write R/Q, it is R but not Q?
If it is so, that is i've said: if n is a number of Q, then, you can find p and q of N, so that and n has a periodic writing.

In romania we say that a number not in Q but in R exemple sqrt(2)
this category of number we say that the are I(irational)

[acoustica]

In romania we say that a number not in Q but in R exemple sqrt(2)
this category of number we say that the are I(irational)

OK :happy2:
Everything is alright?

[Branza]

OK :happy2:
Everything is alright?

yes but yest i think that the solution is very short.

[acoustica]

yes but yest i think that the solution is very short.

Yes, the idea is quite short. It's more difficult to explain with a clean demonstration.

[Branza]

Yes, the idea is quite short. It's more difficult to explain with a clear demonstration.

thank you very much for you contribution.a appreciate that ehat you done.
thanks again.

[acoustica]

See you later in "Maths-Forum"! :++:

[Clembou]

thank you very much for you contribution.a appreciate that ehat you done.
thanks again.

Your problem is "proove that 0,1234567891011... is irrational". And the answers is because that number have a infinite periodic development.

[ThSQ]

This is Champernowne constant :

http://en.wikipedia.org/wiki/Champernowne_constant
http://mathworld.wolfram.com/ChampernowneConstant.html

Decimal digits are obviously not periodic (for instance the number of successive 0 is not bounded).