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Posté par oscar
Bonjour
n1=v2/(2-v3) +1/2(16-2v3)-3v3=v2(2+v3)/(4-3) +8 -v3-3/v3 =2v2 + v6+8--2v3 n2=(v5+v11)/(v11-v5) -v55/3+28/3=(1) (v5+v11)/(v11-v5)= (v5+v11)(v11+v5)/(11-5)=(5+2v55+11)/6= (16+2v55)/6=(8+v55)/3 (1) devient 1/3(8+v55-v55+28)=1/3(33)=11 n1 > n2 ![]() |

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