Osmoralité

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tom77380
Messages: 2
Enregistré le: 17 Jan 2008, 18:36

Osmoralité

par tom77380 » 17 Jan 2008, 18:40

BOnjour à tous, voici l'énoncé du problême :

Une membrane uniquement perméable à l'eau sépare initialement en 2 parties égales un récipient dylindrique de volume total V = 26 L, et de section S = 100 cm². On dissout m1 = 23,2 g de NACL dans le compartiment 1 et m2 = 66g de CaCl2 dans le compartiment 2. La membrane est libre et se déplace sans frottements.

1) Les 2 composés se disolvent. combien de molécules de chaques susbtances correspondent aux masses m1 et m2 ?

2) Exprimer la préssion osmotique dans chaque compartiment.

3) Calculer la position d'équilibre de la membrane.

Données Mca = 40 g Mna = 23g Mcl = 35,5 g

1) j'ai calculé en utilisant la formule n = m/M et j'ai trouvé Nnacl = 3,9 10^-1 et Ncacl2 = 5,9.10^-1

2) Alors là j'ai un gros doute, deja je dois convertis en mol/m cube ce qui me fait donc 390 et 590, ensuite comme sa se dissout, je dois multiplier la concentration par 2 non ? la formule était P osmotique = cRT

MOn problême est pour calculer ce fameux c je suis vraiment perdu, et la température, je supore qu'on prends 25° soit 298 K, la température ambiante.

Merci à vous



tom77380
Messages: 2
Enregistré le: 17 Jan 2008, 18:36

par tom77380 » 17 Jan 2008, 20:12

Un grand merci à toi Quidam, en effet on me demandait le nombre de molécule et mes calculs sont éronnés, idem pour les simplifications...

Merci à toi d'avoir pris le temps de me répondre, et de concevoir une réponse aussi complète et précise, j'ai réussi tout l'éxercice en grande partie grace à toi.

" Toute ma science a été acquise il y a dix minutes, lorsque j'ai consulté Wikipédia !"

Alors là chapeau !

Bonne soirée et merci encore :)

Wrafrurry
Messages: 1
Enregistré le: 11 Avr 2012, 21:56

Crm Magazine

par Wrafrurry » 11 Avr 2012, 21:56

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